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28=2*22+2x^2/2
We move all terms to the left:
28-(2*22+2x^2/2)=0
We get rid of parentheses
-2x^2/2+28-2*22=0
We multiply all the terms by the denominator
-2x^2+28*2-(2*22)*2=0
We add all the numbers together, and all the variables
-2x^2+28*2-44*2=0
We add all the numbers together, and all the variables
-2x^2-32=0
a = -2; b = 0; c = -32;
Δ = b2-4ac
Δ = 02-4·(-2)·(-32)
Δ = -256
Delta is less than zero, so there is no solution for the equation
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